Answer:
The work done on the system is 17.75_KJ
Explanation:
To solve this question we need to know the required equations from the given variables, thus
Initial volume = 85L
Final volume = 12L
External pressure = 2.4 atm.
work done = - PΔV
2.4×(85-12) = 175.2L×atm
Converting from L•atm to KJ is given by
1 L•atm = 0.1013 kJ
(175.2 L•atm) * (0.1013 kJ / 1 L•atm)
= 17.75 kJ
The work done on the system is 17.75_KJ
The work done on the system is -17.75 kJ.
Work done is obtained using the relation;
w = PΔV
where;
w = work done
V = change in volume
V1 = 85 L
V2 = 12 L
P = 2.4 atm
Hence;
w = 2.4 atm(12 - 85) L = -175.2 atm L
Now;
1 L atm = 101.325 J
-175.2 atm L = -175.2 atm L × 101.325 J/1 L atm = -17.75 kJ
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