Average acceleration of the baseball: [tex]-101 m/s^2[/tex]
Explanation:
Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the displacement of the object
For the baseball in this problem, we have:
u = 2.2 m/s is the initial velocity
v = 0 is the final velocity (it comes to a stop)
s = 24 mm = 0.024 m is the displacement of the ball while decelerating
Therefore, we can solve for a to find the acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2[/tex]
where the negative sign means the baseball is slowing down.
Learn more about acceleration:
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