Respuesta :
Answer:
[tex]-3.896\times 10^{-12} N[/tex] is an electric force on the potassium ion due to the chloride ion.
Explanation:
Charge on potassium ion = [tex]q_1=1.602\times 10^{-19} C[/tex]
Charge on chlorine ion = [tex]=q_2=-1.602\times 10^{-19} C[/tex]
Separation between these two charges = r = [tex]7.700 nm=7.700\times 10^{-9} m[/tex]
[tex]1 nm=10^{-9} m[/tex]
Electric force on the potassium ion due to the chloride ion = F
Coulomb's law is given as ;
[tex]F=K\times \frac{q_1\times q_2}{r^2}[/tex]
[tex]q_1,q_2[/tex] = Charges on both charges
r = distance between the charges
K = Coulomb constant =[tex]9\times 10^{9} N m^2/C^2[/tex]
[tex]F=9\times 10^{9} N m^2/C^2\times \frac{1.602\times 10^{-19} C\times (-1.602\times 10^{-19} C)}{(7.700\times 10^{-9} m)^2}[/tex]
[tex]F=-3.896\times 10^{-12} N[/tex]
(negative sign indicates that attractive force is exerting between two ions)
[tex]-3.896\times 10^{-12} N[/tex] is an electric force on the potassium ion due to the chloride ion.
