You are on the ground and observing a jet traveling in air at a constant height of 4500 m with a speed of 650 m/s. How long after the spaceship has passed directly overhead will the shock wave reach you

Respuesta :

Answer:

[tex]t=11.1s[/tex]

Explanation:

Given data

Jet Speed v=650 m/s=1.89504 mach

height h=4500 m

Speed of the Sound V=343 m/s

To find

time t

Solution

As we know that

[tex]Vs_{Velocity}=d_{distance} /t_{time} \\d=Vs*t[/tex]

where

[tex]Vs=1.895*V[/tex]

Also from trigonometric properties we know that

[tex]tan\alpha =\frac{Perpendicular}{Base}[/tex]

We have use height h as perpendicular and distance d is base

So

[tex]tan\alpha =h/d\\tan\alpha=h*(1/Vs*t)\\t=\frac{h}{tan\alpha } \frac{1}{Vs}\\[/tex]

First we need to angle α

Since

[tex]Sin\alpha =V/Vs[/tex]

[tex]Sin\alpha =\frac{v}{1.895v}\\\alpha =32^{o}[/tex]

Substitute given values and angle to  find

[tex]t=\frac{h}{tan\alpha } \frac{1}{Vs}\\t=\frac{4500m}{tan(32) } \frac{1}{1.895*343m/s}\\t=11.1s[/tex]

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