Answer:
Therefore the depth in the ocean at which the presser is three times atmospheric presser is 20.15 m.
Explanation:
The pressure at some depth
[tex]P=P_\circ +\rho gh[/tex] Â
[tex]P_\circ=[/tex] atmospheric presser = [tex]1.013\times 10^5[/tex] Pa
[tex]\rho=[/tex] density of the sea [tex]= 1025 kg / m^3[/tex]
g = gravity = 9.81 m/s²
h = depth of the ocean
P= atmospheric presser at depth = [tex]3P_\circ[/tex]
Therefore
[tex]3P_\circ=P_\circ +\rho gh[/tex]
[tex]\Leftrightarrow \rho gh=2P_\circ[/tex]
[tex]\Leftrightarrow h=\frac{2P_\circ}{\rho g}[/tex]
[tex]\Leftrightarrow h=\frac{2 \times 1.013 \times 10^5}{1025 \times 9.81}[/tex]
[tex]\Leftrightarrow h= 20.15[/tex]
Therefore the depth in the ocean at which the presser is three times atmospheric presser is 20.15 m.
