[tex]\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7}) = \frac{7-9h}{7}[/tex]
Solution:
Given expression is:
[tex]\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})[/tex]
We have to combine the like terms
From given expression,
[tex]\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})[/tex]
By distributive property,
The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.
a(b + c) = ab + bc
Therefore,
Solve for brackets using distributive property
[tex]\frac{1}{7} - (3 \times \frac{3}{7}h) + (3 \times \frac{2}{7})\\\\\frac{1}{7} - \frac{9h}{7} + \frac{6}{7}[/tex]
Add 1/7 and 6/7
[tex]\frac{1}{7} + \frac{6}{7} -\frac{9h}{7}\\\\\frac{1+6}{7} -\frac{9h}{7}\\\\Simplify\\\\\frac{7}{7}-\frac{9h}{7}\\\\1-\frac{9h}{7}\\\\Simplify\\\\\frac{7-9h}{7}[/tex]
Thus the equivalent expression is found