This is an incomplete question, here is a complete question.
A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.
What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.
Answer : The pressure difference will be, [tex]1.11\times 10^3Pa[/tex]
Step-by-step explanation :
As we are given:
Speed = 150 km/h = 41.66 m/s
Density = [tex]\rho=1.28kg/m^3[/tex]
Area = A = 7.00 m × 12.0 m
Formula used :
[tex]\Delta P=\frac{1}{2}\times \rho \times v^2[/tex]
Now put all the given values in this formula, we get:
[tex]\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2[/tex]
[tex]\Delta P=1.11\times 10^3Pa[/tex]
Thus, the pressure difference will be, [tex]1.11\times 10^3Pa[/tex]