Answer:
Yes it is a function given by f(x) = 2x
Step-by-step explanation:
Any function can approximated as series or a polynomial. For example,
[tex]e^{x} = 1 + \frac{x}{1!} + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} ...[/tex] (exponential function)
(n! or n factorial is equal to n(n-1)(n-2)...3.2.1 ; 3! = 3.2.1 = 6)
and for the series to converge(the sum does not go to infinity), higher order terms must tend to zero.
General form of a polynomial/series: [tex]f(x) = a + bx +cx^{2} + ...[/tex]
For the given set of points, we can start with the straight line equation:
[tex]f(x) = y = a + bx[/tex] ........(1)
Let us take two points from the given relation: (-5, -10), (-1, -2)
and put the respective x and y values in equation (1), we get two equations, which we can then solve simultaneously to get values of [tex]a[/tex] and [tex]b[/tex]:
[tex]-10=a-5b[/tex] ........(2)
[tex]-2=a-b[/tex] ..........(3)
Now (3) - (2) gives us: [tex]b=2[/tex] and putting the value of [tex]b[/tex] in any of the above equation gives us [tex]a=0[/tex]
Hence, we get the equation, [tex]f(x)=y=2x[/tex]
It can be seen that all the given points satisfies this relation and since we get a unique [tex]y[/tex] for every [tex]x[/tex], we can call this a function.