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The terminal ray of angle β , drawn in standard position, passes through the point (−5, 2√7) . What is the value of cos β ? Enter your answer, in simplest radical form, in the box.

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Step-by-step explanation:

Draw the triangle formed by the ray.

The hypotenuse of the triangle is:

c² = a² + b²

c² = (-5)² + (2√7)²

c² = 25 + 28

c = √53

Therefore:

cos β = -5 / √53

Or, as a proper fraction:

cos β = -5√53 / 53

Ver imagen MathPhys

The value of cos β is -5√53 / 53

Given that,

  • The terminal ray of angle β , drawn in standard position, passes through the point (−5, 2√7) .

The calculation is:

The hypotenuse of the triangle is:

[tex]c62 = a^2 + b^2\\\\c^2 = (-5)^2 + (2\sqrt7)^2\\\\c^2 = 25 + 28\\\\c = \sqrt53[/tex]

Therefore:

cos β = -5 / √53

Or, a proper fraction:

cos β =  -5√53 / 53

Find out more information about cos here:

https://brainly.com/question/2193114?referrer=searchResults

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