The solutions are [tex]x=15, x=-8[/tex] and [tex]x=9[/tex]
Explanation:
Part a: The equation is [tex]\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)[/tex]
Let us find the value of x.
Multiply the terms within the bracket, we get,
[tex]\frac{5}{3} x-3=\frac{2}{3} x+12[/tex]
Subtracting both sides by [tex]\frac{2}{3} x[/tex], we have,
[tex]\frac{3}{3} x-3=12[/tex]
Adding both sides by 3,
[tex]x=15[/tex]
Thus, the solution of the equation [tex]\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)[/tex] is [tex]x=15[/tex]
Part b: The equation is [tex]4(3x+5)-3=9x-7[/tex]
Multiply the terms within the bracket, we get,
[tex]12x+20-3=9x-7[/tex]
Subtracting both sides by 9x, we have,
[tex]3x+17=-7[/tex]
Subtracting both sides by 17,
[tex]3x=-24[/tex]
Dividing both sides by 3, we have,
[tex]x=-8[/tex]
Thus, the solution of the equation [tex]4(3x+5)-3=9x-7[/tex] is [tex]x=-8[/tex]
Part c: The equation is [tex]5(x+7)-3(x-4)=7x+2[/tex]
Multiply the terms within the bracket, we get,
[tex]5x+35-3x+12=7x+2[/tex]
Adding the like terms, we have,
[tex]2x+47=7x+2[/tex]
Subtracting both sides by 2 and 2x, we get,
[tex]45=5x[/tex]
Dividing both sides by 5, we have,
[tex]x=9[/tex]
Thus, the solution of the equation [tex]5(x+7)-3(x-4)=7x+2[/tex] is [tex]x=9[/tex]
Answer:
The equation is
Let us find the value of x.
Multiply the terms within the bracket, we get,
Subtracting both sides by , we have,
Adding both sides by 3,
Thus, the solution of the equation is
Part b: The equation is
Multiply the terms within the bracket, we get,
Subtracting both sides by 9x, we have,
Subtracting both sides by 17,
Dividing both sides by 3, we have,
Thus, the solution of the equation is
Part c: The equation is
Multiply the terms within the bracket, we get,
Adding the like terms, we have,
Subtracting both sides by 2 and 2x, we get,
Dividing both sides by 5, we have,
Thus, the solution of the equation is
Step-by-step explanation:
