Answer:
Explanation:
Given
Height of ceiling is [tex]h=3.6\ m[/tex]
Initial speed of Putty [tex]u=9.5\ m/s[/tex]
Speed of Putty just before it strike the ceiling is given by
[tex]v^2-u^2=2as[/tex]
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
[tex]v^2-9.5^2=2\times (-9.8)\times 3.6[/tex]
[tex]v^2=19.69[/tex]
[tex]v=4.43\ m/s[/tex]
time taken by putty to reach the ceiling
[tex]v=u+at[/tex]
[tex]4.43=9.5-9.8\times t[/tex]
[tex]t=\frac{5.07}{9.8}[/tex]
[tex]t=0.517\ s[/tex]
