Answer: the average speed of the rat from the information given above is 0.7m/s
Explanation:
position is given as
x(t) = pt² + qt
finding the diffencial of x(t) with respect to t, we have
d(x(t))/dt = 2pt + q
we substitute the p = 0.36m/s² and q= -1.10 m/s
d(x(t))/dt = 2(0.36)t + (-1.10)
so, at t= 1s
d(x(t))/dt = 2*(0.36)*1 - 1.1 = 0.72 - 1.1 = -0.38m/s
at t= 4s
d(x(t))/dt = 2*(0.36)*4 - 1.10 = 2.88 - 1.10 = 1.78 m/s
To find the average speed,
average speed = (V1 + V2)/ 2
average speed = (1.78 + (-0.38))/2 = 0.7m/s
The speed is defined as the distance per unit of time. The unit of speed is m/s. The speed is a scalar quantity which means it only depends on the magnitude.
According to the question, The average speed of the mouse is 0.7m/s
The solution of the question is as follows:-
The required equation is:-
[tex]x(t) = pt^2 + qt[/tex]
The Finding the differential of x(t) with respect to t, we have
[tex]\frac{dxt}{dt} = 2pt + q[/tex]
Put the value p = 0.36m/s² and q= -1.10 m/s
[tex]\frac{d(x(t)}{dt} = 2(0.36)t + (-1.10)[/tex]
so, at t= 1s
After solving it [tex]2*(0.36)*1 - 1.1 = 0.72 - 1.1 = -0.38m/s[/tex]
so,at t= 4s
After solving it =[tex]2*(0.36)*4 - 1.10 = 2.88 - 1.10 = 1.78 m/s[/tex]
The formula of average speed = [tex]\frac{(V1 + V2)}{2}[/tex]
[tex]= \frac{(1.78 + (-0.38))}{2} = 0.7m/s[/tex]
Hence, the average speed is 0.7m/s
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https://brainly.com/question/22610586
