Answer:
0.3859
Step-by-step explanation:
Assuming on the average, a jar of peanut butter contains 452 grams, with a standard deviation of 10.4 grams.
Then we have
[tex] \mu = 452 \: and \: \sigma = 10.4[/tex]
We want to find the probability that a jar contains less than 449 grams.
We first determine the z-score of x=449 grams using:
[tex]z = \frac{x - \mu}{ \sigma} [/tex]
We plug in these values to get:
[tex]z = \frac{449 - 452}{10.4} [/tex]
[tex]z = \frac{ - 3}{10.4} = - 0.29[/tex]
Now we read from the standard normal distribution table the area that corresponds to a z-score of -0.29
P(X<449)=0.3859
