Answer:
The lengths of side A is 22.4 and B is 11.9.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be [tex]x.[/tex]
So, the side A be [tex]2x.[/tex]
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²
[tex](2x)^2+(x)^2=(25)^2[/tex]
[tex]4x^2+x^2=625[/tex]
[tex]5x^2=625[/tex]
Dividing both sides by 5 we get:
[tex]x^2=125[/tex]
Using square root on both sides we get:
[tex]x=11.18.[/tex]
B rounding to the nearest tenth = 11.9.
Now, to get A by substituting the value of [tex]x[/tex]:
[tex]2x\\=2\times 11.18\\=22.36.[/tex]
A rounding to the nearest tenth = 22.4.
Therefore, the lengths of side A is 22.4 and B is 11.9.
