Answer:
[tex]-5.226\times 10^{-7} C[/tex] is the charge on each sphere.
Explanation:
Coulomb's law is given as ;
[tex]F=K\times \frac{q_1\times q_2}{r^2}[/tex]
[tex]q_1,q_2[/tex] = Charges on both charges
r = distance between the charges
K = Coulomb constant =[tex]9\times 10^{9} N m^2/C^2[/tex]
We have ;
Charge of ion =[tex]q_1=-q[/tex]
Charge of electron =[tex]q_2=-q[/tex]
[tex]r=26.55 cm =0.2655 m[/tex]
Force between the charges at r distance will be : F
F = 0.03500 N
[tex]0.03500 N=9\times 10^{9} N m^2/C^2\times \frac{(-q)\times (-q)}{(0.2655 m)^2}[/tex]
[tex]q=5.226\times 10^{-7} C[/tex]
[tex]-5.226\times 10^{-7} C[/tex] is the charge on each sphere.
