sinusoidal wave is described by the wave function y 5 0.25 sin (0.30x 2 40t) where x and y are in meters and t is in seconds. Determine for this wave (a) the amplitude, (b) the angular frequency, (c) the angular wave number, (d) the wavelength

Respuesta :

Answer: Amplitude = 50.25m, angular frequency ([tex]y = A sin (kx -wt)[/tex]) = 240rad/s, wave number (k) = 0.30, wavelength (λ) = 0.047m

Explanation: The equation of wave from the question (corrected) is

[tex]y = 50.25 sin ( 0.30x - 240t)[/tex]

by comparing this to the general equation of a wave (in the negative direction) is given below

[tex]y=Asin (kx - wt )[/tex]

a)

we have that A = 50.25m

b)

-ωt = 240t, thus

ω= 240 rad/s

c) kx = 0.30x , thus

k= 0.30

d) to get wavelength, we use the formulae below

k = 2π/λ

0.30 = 2* 3.142/λ

λ = 2 * 3.142/ 0.30

λ = 0.047m

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