Respuesta :
Answer:
Therefore side B= 11.18 and side A=2×11.18=22.36.
Step-by-step explanation:
Given,side A is twice as long as B and C is 25.
Let side B= x
Then side A = 2x
Using Pythagorean Theorem,
A²+B²=C²
⇔(2x)²+x²=25²
⇔4x²+x²=625
⇔5x²=625
⇔x²=125
⇔x=√125
⇔x =11.18
Therefore side B= 11.18 and side A=2×11.18=22.36.
Answer:
The length of side A is 22.4 and length of side B is 11.9.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25.
Solve by using the Pythagorean Theorem.
Now, to get the lengths of side A and side B.
As side C = 25.
Let the side B be [tex]a.[/tex]
As, given A is twice as long as B.
So, the side A be [tex]2a.[/tex]
So, we solve by using Pythagorean Theorem:
A² + B² = C²
[tex](2a)^2+(a)^2=(25)^2[/tex]
[tex]4a^2+a^2=625[/tex]
[tex]5a^2=625[/tex]
Dividing both sides by 5 we get:
[tex]a^2=125[/tex]
So, using square root on both sides we get:
[tex]a=11.18.[/tex]
Rounding to the nearest tenth B = 11.9.
Now, to get A by putting the value of [tex]a[/tex]:
[tex]2a\\=2\times 11.18\\=22.36.[/tex]
Rounding to the nearest tenth A = 22.4.
Therefore, the length of side A is 22.4 and length of side B is 11.9.
