The equation of line EF is y = -1/2x + 6. What is the equation of a line parallel to line EF in slope-intercept form that contains point (0, −2)?
y = −2x − 2
y = -1/2x + 2
y = -1/2x − 2
y = −2x + 2

Respuesta :

Answer:

the answer is Y=-1/2x - 2

Step-by-step explanation:

1. Y=-1/2x + 6 since both lines are parrellel they use the same slope

M=  -1/2

and you put it in point slope form (y-y1) = M(x-x1)

use point (0,-2) becuase the line has to go through this point

(y-(-2)= -1/2(x-0)   (y+2)= -1/2x    then you change it in to slope intercept form

(y+2)= -1/2x

  -2            -2

y=-1/2x -2

The equation of a line parallel to line EF in slope-intercept form is  ,[tex]y=-\frac{1}{2}x-2[/tex]

The slope of parallel lines will be always same.

Given that,

The equation of line EF is,   [tex]y = -\frac{1}{2} x + 6.[/tex]

Compare above equation with [tex]y=mx+c[/tex]

We get,           [tex]Slope(m)=-\frac{1}{2}[/tex]

So that line parallel to line EF will also have slope of [tex]-\frac{1}{2}[/tex].

Equation of parallel line is,

                           [tex]y=-\frac{1}{2}x+c[/tex]

Substitute point  (0, −2) in above equation.

   We get,          [tex]c=-2[/tex]

Hence, equation is,  [tex]y=-\frac{1}{2}x-2[/tex]

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