Respuesta :
Answer:
The excess charge on earth's surface was calculated to be 4.56 × 10⁵ C
Explanation:
Using the formula for an electric field;
E = kQ/r²
k = 1/(4πε₀) = 8.99 × 10⁹ Nm²/C²
E = 100N/C
r = radius of the earth = 6400 km = 6400000m
Q = Er²/k = 100 × (6400000)²/(8.99 × 10⁹)
Q = 455617.4 C = 4.56 × 10⁵ C
Hope this helps!!!
The excess charge on the surface of the earth is 4.55×10⁵C
To calculate the charge on the surface of the earth, we apply the equation of electric field strength, that is:
[tex]E = k\frac{Q}{r^2}[/tex]
here, E is the electric field strength = 100N/C (given)
k = 9×10⁹ Nm²/C²
Q is the charge, and
r = distance = radius of earth = 6.4×10⁶ m
Now,
[tex]Q = \frac{r^2E}{k}\\ \\=\frac{(6.4*10^6)^2*100}{9*10^9}\\\\Q=4.55*10^5 C[/tex] is the charge acquired on the surface of the earth.
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