Respuesta :
Answer:
The swimming pool will contain approx [tex]8243\ gal[/tex] of water.
Step-by-step explanation:
Given the swimming pool is in a cylindrical shape.
And the dimensions are [tex]20\ feet[/tex] diameter with a height of [tex]3.5\ feet.[/tex]
Also, [tex]1\ ft^3 =7.5\ gal[/tex]
First, we will find the volume of the swimming pool.
The swimming pool is in cylindrical shape.
So, the volume would be [tex]\pi r^2h[/tex]
The height [tex](h)[/tex] is given as [tex]3.5\ feet.[/tex] To calculate radius [tex](r)[/tex] we will divide the diameter by two.
The radius of the cylinder would be [tex]\frac{20}{2}=10\ feet[/tex]
Plug these values in the formula we get,
[tex]\pi r^2h\\=\pi\times 10^2\times 3.5\\=3.14\times 100\times 3.5\\=1099\ ft^3[/tex]
Now, it is given [tex]1\ ft^3 =7.5\ gal[/tex]
So, [tex]1099\ ft^3 =1099\times 7.5\ gal=8242.5\ gal[/tex]
The swimming pool will contain approx [tex]8243\ gal[/tex] of water.
