Respuesta :
Answer:
Workdone = 12.2 Joules
Explanation:
Given:
Force applied on the pencil = 47 N
Displacement of the pencil = 0.26 m
We have to find the work done .
Note:
Workdone = Product of force and its displacement (in the direction of the force) .
So,
Plugging the values.
Workdone = [tex]Force\times displacement[/tex]
⇒ [tex]W=F\times d[/tex]
⇒ [tex]W =47\times 0.26[/tex]
⇒ [tex]W=12.2[/tex] Joules (J)
OR
We can say that the displacement is against the direction of applied force.
Displacement = - 0.26
Workdone = [tex]F\times d\times cos(\theta)[/tex]
⇒ [tex]\theta[/tex] is the angle between force and displacement.
⇒ Here, [tex]\theta=180[/tex]
⇒ [tex]cos(180) = -1[/tex]
Workdone (W) = [tex]Fdcos(\theta)[/tex]
⇒ [tex]47\times -0.26\times -1[/tex]
⇒ [tex]12.2[/tex] Joules (J).
Workdone on pushing the pencil = 12.2 Joules.
Work is the product of the force and displacement. The work done by in the given situation 12.2 J.
Work:
It is the change in the energy due displacement of the object by the applied force. Work is the product of the force and displacement.
W = f.d
Where,
W - work
f- force = 47 N
d - displacement = 0.26 m.
put the values in the formula,
W = 47 N x 0.26 m.
W = 12.2 J
Therefore, the work done by in the given situation 12.2 J.
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