Answer:The moon will recoil at 1.019×10^-6m/s
Explanation:To determine the recoil velocity of the moon after the inelastic collisions
Given:
Mass of moon=7.36×10^22kg=m1
Mass of asteroids = 5×10^12=m2
Initial velocity of moon =0
Initial velocity of asteroids =15km/s=15000m/s
The law of conservation of momentum is given as
M1v1 + m2v2 =(m1+m2)v'
O + m2v2= (m1 +m2)v'
V'=m2v2/(m1+m2)
V'=(5×10^22)×15000/(7.36×10^22)+(5×10^12)
V'=1.019×10^-6m/s
Answer:
The moon will recoil at the speed of 1.019×10^-6 m/s the whole mass
Explanation:
Mass of moon=7.36×10^22kg=m1
Mass of asteroids = 5×10^12=m2
Initial velocity of moon =0
Initial velocity of asteroids =15km/s=15000m/s
The law of conservation of momentum is given as
M1v1 + m2v2 =(m1+m2)v'
0 + m2v2= (m1 +m2)v'
V'=m2v2/(m1+m2)
V'=(5×10^22)×15000/(7.36×10^22)+(5×10^12)
V'=1.019×10^-6m/s
Please find the attached picture to get the full explanation.
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