Write the rate law for the reaction 2A + B → C if the reaction

(1) is second order in B and overall third order, –rA = ______

(2) is zero order in A and first order in B, –rA = ______

(3) is zero order in both A and B, –rA = ______

(4) is first order in A and overall zero order. –rA = ______

Respuesta :

Answer:

1.   [tex]R=k[A]^1[B]^2[/tex]

2.  [tex]R=k[B]^1[/tex]

3.  [tex]R=k[A]^0[B]^0=k[/tex]

4.  [tex]R=k[A]^1[B]^{-1}[/tex]

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

(1) is second order in B and overall third order.

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= x + 2 = 3

x = 1

Rate of the reaction =R

[tex]R=k[A]^1[B]^2[/tex]

(2) is zero order in A and first order in B.

2A + B → C

Rate of the reaction =R

[tex]R=k[A]^0[B]^1=k[B]^1[/tex]

Order of the reaction = sum of stoichiometric coefficient

= 0 + 1 = 1

(3) is zero order in both A and B .

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= 0 + 0 = 0

Rate of the reaction =R

[tex]R=k[A]^0[B]^0=k[/tex]

(4) is first order in A and overall zero order.

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= 1 + x = 0

x = -1

Rate of the reaction = R

[tex]R=k[A]^1[B]^{-1}[/tex]

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