x ≤ 12
Solution:
Let us take the number be x.
A number : x
A number divided by three : [tex]$\frac{x}{3}[/tex]
A number divided by three less two : [tex]$\frac{x}{3}-2[/tex]
A number divided by three less two is at most two : [tex]$\frac{x}{3}-2\leq 2[/tex]
Now, simplify the inequality,
[tex]$\Rightarrow\frac{x}{3}-2\leq 2[/tex]
Add 2 on both sides of the inequality,
[tex]$\Rightarrow\frac{x}{3}-2+2\leq 2+2[/tex]
[tex]$\Rightarrow\frac{x}{3}\leq 4[/tex]
Multiply by 3 on both sides of the equation,
[tex]$\Rightarrow\frac{x}{3}\times3\leq 4\times3[/tex]
[tex]$\Rightarrow x\leq 12[/tex]
Hence x ≤ 12.
