Answer:
The answer to your question is 8.67 grams of Al₂O₃
Explanation:
Data
mass of Al₂O₃ = ?
mass of Al = 4.6 g
mass of O₂ = excess
Balanced Reaction
4Al + 3O₂ ⇒ 2Al₂O₃
Reactants Elements Products
4 Al 4
6 O 6
Process
1.- Use proportions to calculate the moles of Al
27 g of Al ------------------ 1 mol
4.6 g of Al ------------------ x
x = 0.17 mol of Al
2.- use proportions to calculate the moles of Al₂O₃
4 moles of Al ------------------ 2 moles of Al₂O₃
0.17 moles of Al -------------- x
x = 0.085 moles of Al₂O₃
3.- Use proportions to calculate the grams of Al₂O₃
molecular mass Al₂O₃ = (27 x 2) + (16 x 3) = 102 g
102 g of Al₂O₃ --------------- 1 mol
x --------------- 0.085 moles
x = 8.67 g of Al₂O₃
