Answer:
298.32 grams
Explanation:
Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 3088 J
m = mass = ??
Cp = Specific Heat Capacity = 0.897 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = 26.31 °C - 14.77 °C = 11.54 °C
Solving eq. 1 for m,
m = Q / Cp ΔT
Putting values,
m = 3088 J / (0.897 J.g⁻¹.°C⁻¹ × 11.54 °C)
m = 298.32 g
