if a material has a half-life of 24 hours, how long do you have to wait until the amount of radioisotope is 1/4 its original amount?

Respuesta :

Answer:

48 hours

Explanation:

Using the formula,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original amount, R' = Radioactive remain, a = Total time, b = half life.

Given: b = 24 hours,

Let: R = X, then R' = X/4.

Substitute into equation 1

X/(X/4) = 2ᵃ/²⁴

4 = 2ᵃ/²⁴

2² = 2ᵃ/²⁴

Equating the base and solving for a

2 = a/24

a = 24×2

a = 48 hours.

Hence the time = 48 hours

The time taken will be "t = 24 hrs".

According to the question,

half life period of sample is:

  • [tex]T_{\frac{1}{2} } = 12 \ hours[/tex]

Initially there are [tex]N_o[/tex] atoms in the sample.

Finally there are [tex]\frac{N_o}{4}[/tex] atoms in the sample.

Let,

  • The time taken be "t".

Now,

→ [tex]N = N_o e^{- \lambda t}[/tex]

  [tex]\frac{N_o}{4} = N_o e^{\lambda t}[/tex]

   [tex]\lambda t = -ln(\frac{1}{4} )[/tex]

[tex]\frac{0.693}{T_{1/2}} = -ln(\frac{1}{4} )[/tex]

     [tex]t = \frac{-ln(0.25)\times 12}{0.693}[/tex]

        [tex]= 24 \ hours[/tex]

Thus the above answer is correct.

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