Q: How much heat must be absorbed by 125 g of ethanol to change its temperature from 21.5 oC to 34.8 oC? The specific heat of ethanol is 2.44 J/(gC).
Answer:
4056.5 J
Explanation:
The formula for the specific heat capacity of ethanol is given as
Q = cm(t₂-t₁)..................... Equation 1
Where q = quantity of heat, c = specific heat capacity of ethanol, m = mass of ethanol, t₁ = initial temperature of ethanol, t₂ = final temperature of ethanol.
Given: m = 125 g, t₁ = 25.5 °C, t₂ = 34.8 °C
Constant; c = 2.44 J/g.°C
Substitute into equation 1
Q = 125(2.44)(34.8-21.5)
Q = 125(2.44)(13.3)
Q = 4056.5 J.
Hence the amount of heat absorbed = 4056.5 J
