Respuesta :
Answer:
b. From 33 km/h to 43 km/h
Explanation:
Lets take mass of the car = m
We know that The change kinetic energy KE is give as
[tex]KE=\dfrac{1}{2}m(v^2-u^2)[/tex]
When speed changes from 23 km/h to 33 km/h :
We know that 1 km/h= 0.27 m/s
[tex]KE=\dfrac{1}{2}m(v^2-u^2)[/tex]
[tex]KE=\dfrac{1}{2}\times m((0.27\times 33)^2-(0.27\times 23)^2)[/tex]
KE= 20.412m J
When speed changes from 33 km/h to 43 km/h :
We know that 1 km/h= 0.27 m/s
[tex]KE=\dfrac{1}{2}m(v^2-u^2)[/tex]
[tex]KE=\dfrac{1}{2}\times m((0.27\times 43)^2-(0.27\times 33)^2)[/tex]
KE= 27.702m J
Therefore we can say that when speed changes 33 km/h to 43 km/h ,the kinetic energy will changes more.
