Answer:
Option c
Step-by-step explanation:
given that limit x tending to 4 of the function (3x-4) is 8
This implies for all values of x such that for epsilon >0 arbitrary small ,
[tex]||x-4||<\epsilon[/tex], we get
|f(x)-8|<3epsilon
this is equivalent to the option c.
Proof:
Consider
[tex]||x-4||<\epsilon\\3||x-4||<3\epsilon\\||3x-12||<3\epsilon\\||3x-4|-8| <3\epsilon[/tex]
Hence it follows that option C is right.
