WORTH 100 POINTS
A plane is racing a helicopter to a runway traveling 31 mph and it tends to burn 5 gallons of gas ever 3 minutes. Whilst the helicopter is traveling at a speed of 45 mph burning 7 gallons of gas every 5 minutes. They both started with the same amount of fuel (80 gallons) and both have the same amount to travel ( 640 miles) Who will make it first using the less amount of fuel?
Does this problem work?
If so what is the answer?
Show your work please

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rani01654 rani01654 · Answer 1 · 2020-02-11T12:21:00+01:00

Answer:

The problem does not work.

Step-by-step explanation:

The plane with speed of 31 mph will cover 640 miles in [tex]\frac{640}{31} = 20.64[/tex] hours.

Now, it burns 5 gallons of gas every 3 minutes i.e. 0.05 hours.

So, it will burn in 20.64 hours [tex]\frac{5 \times 20.64}{0.05} = 2064[/tex] gallons.

Now, the helicopter with speed of 45 mph will cover 640 miles in [tex]\frac{640}{45} = 14.22[/tex] hours.

Now, it burns 7 gallons of gas every 5 minutes i.e. 0.083 hours.

So, it will burn in 14.22 hours [tex]\frac{7 \times 14.22}{0.083} = 1194.48[/tex] gallons.

But both of them starts with only 80 gallons of fuel.

Therefore, the problem does not work. (Answer)