Two timpani (tunable drums) are played at the same time. One is correctly tuned so that when it is struck, sound is produced that has a wavelength of 2.20 m. The second produces sound with a wavelength of 2.10 m. If the speed of sound is 343 m/s, what beat frequency is heard?

Respuesta :

Answer:

Explanation:

Given

Wavelength of first timpani [tex]\lambda _1=2.2\ m[/tex]

Frequency corresponding to this Wavelength

[tex]f_1=\frac{v}{\lambda _1}[/tex]

where [tex]v=velocity\ of\ sound (343 m/s)[/tex]

[tex]f_1=\frac{343}{2.2}[/tex]

[tex]f_1=155.9\ Hz[/tex]

Wavelength of Second timpani [tex]\lambda _2=2.1\ m[/tex]

Frequency corresponding to this Wavelength

[tex]f_2=\frac{v}{\lambda _2}[/tex]

[tex]f_2=\frac{343}{2.1}=163.33\ Hz[/tex]

Beat frequency [tex]=f_2-f_1[/tex]

Beat frequency [tex]=163.33-155.9=7.43[/tex]

so approximately 7 beats per second

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