Answer : The pressure in the flask after reaction complete is, 2.4 atm
Explanation :
To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.
[tex]PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}[/tex]
where,
P = final pressure in the flask = ?
R = gas constant = 0.0821 L.atm/mol.K
T = temperature = [tex]25^oC=273+25=298K[/tex]
V = volume = 4.0 L
[tex]n_1[/tex] = moles of [tex]SO_2[/tex] = 0.20 mol
[tex]n_2[/tex] = moles of [tex]O_2[/tex] = 0.20 mol
Now put all the given values in the above expression, we get:
[tex]P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}[/tex]
[tex]P=2.4atm[/tex]
Thus, the pressure in the flask after reaction complete is, 2.4 atm