A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC, what is the pressure in the flask after reaction is complete?

Respuesta :

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

[tex]PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}[/tex]

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = [tex]25^oC=273+25=298K[/tex]

V = volume = 4.0 L

[tex]n_1[/tex] = moles of [tex]SO_2[/tex] = 0.20 mol

[tex]n_2[/tex] = moles of [tex]O_2[/tex] = 0.20 mol

Now put all the given values in the above expression, we get:

[tex]P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}[/tex]

[tex]P=2.4atm[/tex]

Thus, the pressure in the flask after reaction complete is, 2.4 atm

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