Answer:
The new volume is 5.37 L
Explanation:
Step 1: Data given
Initial volume = 10.0 L
Initial temperature = 22.0 °C
Initial pressure = 1.00 atm
Final temperature = 202 °C
Final pressure = 3.00 atm
Step 2: Calculate final volume
(P1*V1)/T1 = (P2*V2)/T2
⇒ with P1 = The initial pressure = 1.00 atm
⇒ with V1 = The initial volume = 10.0 L
⇒ with T1 = The initial temperature = 22 °C = 295 Kelvin
⇒ with P2 = The final pressure = 3.00 atm
⇒ with V2 = The final volume = TO BE DETERMINED
⇒ with T2 = The final temperature = 202 °C = 475 Kelvin
(1.00 * 10.0) / 295 = (3.00 * V2) / 475
10 / 295 = 3V2/ 475
3V2 = 4750/295
V2 = 5.37 L
The new volume is 5.37 L
