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From January 26, 1977, to September 18, 1983, George Meegan of Great Britain walked from Ushuaia, at the southern tip of South America, to Prudhoe Bay in Alaska, covering 30 600 km. What was the magnitude of his average speed during that time period

Respuesta :

Answer:

average speed = 0.146 m/s

Explanation:

given data

distance = 30600 km

time = January 26, 1977 to September 18, 1983

solution

we get here time that is January 26, 1977 to September 18, 1983

so it is = 6 year and 7 months and 22 days

and  that is = 2422 days = 2.09 × [tex]10^{8}[/tex] seconds

and distance is = 30600 km = 30600 × 10³ m

so here average speed will be as

average speed = [tex]\frac{distance}{time}[/tex]        ...........1

average speed = [tex]\frac{30600*10^3}{2.09*10^8}[/tex]

average speed = 0.146 m/s

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