Answer:
E
Step-by-step explanation:
Given the system of two equations:
[tex]\left\{\begin{array}{l}\dfrac{2}{3}x-\dfrac{1}{2}y=1\\ \\-\dfrac{4}{3}x+y=-3\end{array}\right.[/tex]
Multiply the first equation by 6 and the second equation by 3 to eliminate fractions:
[tex]\left\{\begin{array}{l}4}x-3y=6\\ \\-4x+3y=-9\end{array}\right.[/tex]
Add these two equations:
[tex]4x-3y-4x+3y=6-9\\ \\0=-3[/tex]
You get false equality [tex](0\neq -9)[/tex], so the system of two equations has no solution (two equations represent parallel lines)
