Respuesta :
[tex]f(x) = \frac{ax + b}{cx + d} \\ {f}^{ - 1}(x) = \frac{ - dx + b}{cx - a} \\ \\ y = \frac{0x - 3}{x + 4} \\ {y}^{ - 1} = \frac{ - 4x - 3}{x} [/tex]
so the answer is D
[tex]f(x) = \frac{ax + b}{cx + d} \\ {f}^{ - 1}(x) = \frac{ - dx + b}{cx - a} \\ \\ y = \frac{0x - 3}{x + 4} \\ {y}^{ - 1} = \frac{ - 4x - 3}{x} [/tex]
so the answer is D
