Answer:
Electric field, [tex]E=6.02\times 10^{-3}\ N/C[/tex] to the west direction.
Explanation:
Given that,
Acceleration of the electron, [tex]a=1.06\times 10^9\ m/s^2[/tex] (eastwards)
We need to find the magnitude and direction of the electric field. From Newton's law and electrostatic force,
ma = qE
[tex]E=\dfrac{ma}{q}[/tex]
[tex]E=\dfrac{9.1\times 10^{-31}\times 1.06\times 10^9}{1.6\times 10^{-19}}[/tex]
[tex]E=6.02\times 10^{-3}\ N/C[/tex]
The direction of electric field is in opposite direction of the acceleration of the electron. So, the electric field is acting in west direction.
