Answer:
Electric potential, V = 40.68 volts
Explanation:
Given that,
Charge on the sphere, [tex]q=22.6\ pC=22.6\times 10^{-12}\ C[/tex]
Diameter of the plastic sphere, d = 1 cm
Radius, r = 0.5 cm
We need to find the electric potential at its surface. The potential at a surface is given by :
[tex]V=\dfrac{kq}{r}[/tex]
[tex]V=\dfrac{9\times 10^9\times 22.6\times 10^{-12}}{0.5\times 10^{-2}}[/tex]
V = 40.68 volts
So, the electric potential at its surface is 40.68 volts. Hence, this is the required solution.
