100. mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.0766 atm at 25.0 degree C . Calculate the molar mass of the protein. Be sure your answer has the correct number of significant digits.

Respuesta :

Answer:

molar mass is [tex]6.39\times10^3\ g/mol[/tex]

Explanation:

Osmotic pressure is related with concentration as follows:

[tex]\pi =CRT[/tex]

Where, C is concentration or molarity , R is gas constant and T is temperature.

Osmostic pressure given is 0.0766 atm

R is [tex]0.0821 L \ atm \ K^{1}mol^{-1}[/tex]

T = 25 + 273 = 298 K

Rearrange the above equation to calculate concetration of the solution as follows:

C = P/RT

[tex]C=\frac{0.0766}{0.0821 \times 298} \\=0.00313\ M[/tex]

molarity = moles/volume in L

moles = molarity × volume in L

volume = 5.00 mL = 0.005 L

moles = 0.00313 × 0.005

           =[tex]1.565 \times 10^{-5}[/tex]

[tex]molar\ mass=\frac{mass\ in\ g}{moles} \\=\frac{0.1\ g}{1.565\times 10^{-5}mol} \\=6.389\times 10^3\ g/mol\\[/tex]

Therefore, molecular mass of protein is [tex]6.39\times10^3\ g/mol[/tex]

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