Answer:
[tex]\large \boxed{\text{B. 36 apples}}[/tex]
Step-by-step explanation:
Let a = the number of apples
and o = the number of oranges
You have two conditions:
[tex]\begin{array}{lrcl}(1) & \dfrac{a}{o} & = & \dfrac{4}{2} \\\\(2) & a+ o & = & 54\\\end{array}[/tex]
Solve the equations for a
[tex]\begin{array}{rcll}2a & = & 4o & \text{Multiplied each side of (1) by 2o}\\\(3) \,2a - 4o& = & 0 &\text{Subtracted 4o from each side}\\a + o & = & 54& \text{This is equation (2)}\\(4) \, 4a +4o& = &216&\text{Multiplied each side by 4} \\6a& = &216&\text{Added (3) and (4)} \\a & = &\mathbf{36}&\text{Divided each side by 6} \\\end{array}\\\text{Tia should sell $\large \boxed{\textbf{36 apples}}$}[/tex]
