A mass is attached to a spring with spring constant k = 20 N m . The spring is stretched to 10 cm past its resting position. How much work (in J) does the spring do when the object is released and the mass travels back to its initial position?

Respuesta :

The work done by the spring when the object is released and the mass travels back to its initial position is 0.1 J.

The given parameters:

  • Spring constant, k = 20 N/m
  • Extension of the spring, k = 10 cm = 0.1 m

The work done by the spring when the object is released and the mass travels back to its initial position is calculated as follows;

[tex]W = \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 20 \times (0.1)^2\\\\W = 0.1 \ J[/tex]

Thus, the work done by the spring when the object is released and the mass travels back to its initial position is 0.1 J.

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