Answer:
383.18 N are required to lift the statue
Explanation:
Since the statue receives an upward buoyant force that follows the principle of Archimedes ( and is equal to the weight of displaced seawater due to the volume of the statue) , the net force required would be
net force = weight of the statue - upward buoyant force = m*g - ρsw * V *g =
(m- ρsw * V)*g
where
m= mass of the statue = 70.0 kg
V= volume of the statue = = 0.030 m³
g= gravity = 9.8 m/s²
ρsw = mass density of seawater = 1030 kg/m³
replacing values
net force = (m- ρsw * V)*g = (70.0 kg - 1030 kg/m³*0.030 m³)* 9.8 m/s² = 383.18 N
The amount of force needed to lift mass is mathematically given as
Net force= 383.18 N
Question Parameter(s):
A 70.0 kg ancient statue lies at the bottom of the sea
Volume is 30,000 cm3
Where
net force = weight of the statue - upward buoyant force
Generally, the equation for the is mathematically given as
net force = m*g - ρsw * V *g
Therefore
net force = (m- ρsw * V)*g
net force= (70.0 kg - 1030 *0.030 )* 9.8
net force= 383.18 N
In conclusion, The net force is
Net force= 383.18 N
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