Respuesta :
Answer: The solubility product of the given salt is [tex]7.63\times 10^{-5}[/tex]
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
Moles of salt = 0.0410 mol
Volume of solution = 1.00 L
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{0.0410mol}{1.00L}=0.0410M[/tex]
The given chemical equation follows:
[tex]AB_3(s)\rightleftharpoons A^{3+}(aq.)+3B^-(aq.)[/tex]
1 mole of the [tex]AB_3[/tex] salt produces 1 mole of [tex]A^{3+}[/tex] ions and 3 moles of [tex]B^-[/tex] ions
So, concentration of [tex]A^{3+}\text{ ions}=(1\times 0.0410)M=0.0410M[/tex]
Concentration of [tex]B^{-}\text{ ions}=(3\times 0.0410)M=0.123M[/tex]
Expression for the solubility product of will be:
[tex]K_{sp}=[A^{3+}][B^-]^[/tex]
Putting values in above equation, we get:
[tex]K_{sp}=(0.0410)\times (0.123)^3\\\\K_{sp}=7.63\times 10^{-5}[/tex]
Hence, the solubility product of the given salt is [tex]7.63\times 10^{-5}[/tex]
