Determine the formulas for these ionic compounds. copper(I) bromide: copper(I) oxide: copper(II) bromide: copper(II) oxide: iron(III) bromide: iron(III) oxide: lead(IV) bromide: lead(IV) oxide:

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whereisshe whereisshe · Answer 1 · 2020-02-05T20:22:19+01:00

Answer:

copper(I) bromide: CuBr

copper(I) oxide: Cu₂O

copper(II) bromide: CuBr₂

copper(II) oxide: CuO

iron(III) bromide: FeBr₃

iron(III) oxide: Fe₂O₃

lead(IV) bromide: PbBr₄

lead(IV) oxide: PbO₂

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pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-09-18T00:59:11+02:00

The formulas of the ionic compounds are as follows;

copper(I) bromide ----- CuBr

copper(I) oxide ------ Cu2O

copper(II) bromide ----- CuBr2

copper(II) oxide ------- CuO

iron(III) bromide ------ FeBr3

iron(III) oxide ------ Fe2O3

lead(IV) bromide ---- PbBr4

lead(IV) oxide ------ PbO2

The formula of an ionic compound is written with knowledge of the oxidation state of the metal in the ionic compound.

The oxidation state of each atom determines the subscript it carries in the formula as shown in the chemical formulas written above.

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