Respuesta :
Answer: The work required to compress helium gas is 540 kJ
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:
[tex]W=-P\Delta V=-P(V_2-V_1)[/tex]
W = amount of work done = ?
P = pressure = 180 kPa
[tex]V_1[/tex] = initial volume = [tex]5m^3[/tex]
[tex]V_2[/tex] = final volume = [tex]2m^3[/tex]
Putting values in above equation, we get:
[tex]W=-180kPa\times (2-5)m^3=540kPa.m^3[/tex]
To convert this into joules, we use the conversion factor:
[tex]1kPa.m^3=1kJ[/tex]
So, [tex]540kPa.m^3=540kJ[/tex]
The positive sign indicates that work is done by the system.
Hence, the work required to compress helium gas is 540 kJ
