Suppose you want to move a big rock in your yard. It is about waist high and 4 feet long, has a volume of 1.2 m3 and a density of 2.5 g/cm3. How much does it weigh, in units of lbs?

Respuesta :

Answer:

6613.87 lbs

Explanation:

1.2 m³ = 1200000 cm³

Mass = Density * Volume

M = (2.5 g/cm³) * 1200000 cm³ = 3000000 g

1 lb = 453.592 g

3000000 g * (1 lbs / 453.592 g) = 6613.87 lbs

The mass of the rock is 6613.87 lbs.

How do you calculate the Weigh?

Mass is the quantity of matter in a physical body and the weigh is used to measure ascertain the heaviness of by or as if by a balance.

Given that volume of the rock is 1.2 meter cube and density is 2.5 gram/cm cube. The height of the rock is 4 feet. The mass can be calculated as given below.

Mass m = Density w [tex]\times[/tex] Volume v

Substituting the values in the above equation.

[tex]m = 2.5 \;\rm g/cm^3 \times 1.2\;\rm m^3[/tex]

[tex]m = 2.5 \times 1.2 \times 1000000[/tex]

[tex]m = 3000000\;\rm g[/tex]

The mass of the rock is 3000000 g. We know that

[tex]1\;\rm lb = 453.592\;\rm g[/tex]

[tex]1\;\rm g = \dfrac {1}{453.592} \;\rm lb[/tex]

Now convert the mass (grams) into mass (lbs).

[tex]m = \dfrac {1}{453.592}\times 3000000\;\rm lbs[/tex]

[tex]m = 6613.87 \;\rm lbs[/tex]

Hence we can conclude that the mass of the rock is 6613.87 lbs.

To know more about the mass, follow the link given below.

https://brainly.com/question/15959704.

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