You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several different temperatures. The sphere can expand or shrink to any volume without changing the pressure of the gas inside. As a result of your experiment, you find that the volume (V) of the gas divided by its temperature (T) is always equal to 1.75. What would the volume (V) of the gas be at a temperature of 300K? (assume the unit for volume is liters) Show your work and answer the question with a clear statement. Show each step of your calculations for full points. After showing your calculations, answer the question with a clear statement.

According to Charles' law, the volume of a gas is inversely proportional to its absolute temperature when the pressure of the gas is constant.

Here the V/T is given to be constant and equal to 1.75.

The temperature of the gas = T = 300K.

Let the volume of the gas be V liters.

So according to the question,

V / T = 1.75.

So,V / 300 = 1.75.

So, V = 300 × 1.75.

Or, V = 525 litres.

So, the volume of the gas at 300K will be 525 litres.

andromache andromache · Answer 2 · 2022-02-08T16:01:15+01:00

The Volume of the gas at 300K will be 525l liters.

Charles law:

As per Charles' law, the volume of gas should be inversely proportional to the absolute temperature at the time when the pressure of the gas is constant.

Calculation of the volume of the gas:

Here the V/T should be constant and equivalent to 1.75.

The temperature of the gas = T = 300K.

Also, we assume that the volume of the gas is V liters.

So,

V / T = 1.75.

V / 300 = 1.75.

V = 300 × 1.75.

V = 525 litres.

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