Use the ideal gas law to calculate the pressure in atmospheres of 0.214 mol of Helium (He) at 61°C & occupying 2.53 L. You must show all of your work to earn credit. **Don't forget to convert your Celsius temperature to Kelvin. ** (4 points)
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Respuesta :

Pressure is 2.32 atm.

Explanation:

Ideal gas law is given as, PV = nRT

P represents pressure, V represents volume, T represents, temperature in Kelvin, R is nothing but the gas constant, its value is 0.08206 L atm mol⁻¹K⁻¹.

n represents the number of moles.

We have to convert temperature in Kelvin by adding 273 K to the given temperature in Celsius.

Temperature = 61°C + 273 K = 334 K

Plugin the values in the above equation as,

P = [tex]\frac{nRT}{V}[/tex]

  = [tex]\frac{0.214 mol \times0.08206 L atm/mol K\times 334 K }{2.53L}[/tex]

= 2.32 atm  

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