" According to the Joy Cone Company, their waffle cones have a diameter of 2 5/8 inches and a
height of 6 inches.

If you place one scoops of ice cream (in the shape of a sphere) with a diameter of 2 7/8 inches wnd let
it melt, will the cone hold all of the ice cream?
Use mathematics to explain and justify your answer.

Respuesta :

Answer:

No, the cone will not hold all of the ice cream.

Step-by-step explanation:

Given:

" According to the Joy Cone Company, their waffle cones have a diameter of 2 5/8 inches and a  height of 6 inches.

If you place one scoops of ice cream (in the shape of a sphere) with a diameter of 2 7/8 inches would let  it melt.

Now, to explain mathematically will the cone hold all of the ice cream.

Taking the value of π = 3.14.

So, to get the volume of waffle cone we put formula:

Height (h) = 6 inches.

Diameter = [tex]2\frac{5}{8}=\frac{21}{8}\ inches.[/tex]

Thus radius (r) = Diameter ÷ 2 = [tex]\frac{\frac{21}{8}}{2} =\frac{21}{16} \ inches.[/tex]

[tex]Volume=\pi r^2\frac{h}{3}[/tex]

[tex]Volume=3.14\times \frac{21}{16} \times \frac{21}{16} \times \frac{6}{3}[/tex]

[tex]Volume=3.14\times 1.31\times 1.31\times 2[/tex]

[tex]Volume=10.78\ inches^3.[/tex]

The volume of waffle cone = 10.78 inches³.

Now, to get the volume of scoop which is in the shape of sphere we put formula:

Diameter = [tex]2\frac{7}{8} =\frac{23}{8} \ inches.[/tex]

Thus radius (r) = Diameter ÷ 2 [tex]=\frac{\frac{23}{8}}{2} =\frac{23}{16} \ inches.[/tex]

[tex]Volume = \frac{4}{3} \pi r^3[/tex]

[tex]Volume = \frac{4}{3} \times 3.14\times \frac{23}{16} \times \frac{23}{16} \times \frac{23}{16}[/tex]

[tex]Volume=1.33\times 3.14\times 1.44\times 1.44\times 1.44[/tex]

[tex]Volume=12.47\ inches^3.[/tex]

The volume of one scoop of ice cream = 12.47 inches³.

So, as the volume of scoop of ice cream is more than the volume of cone.

Thus, if placing one scoop of ice cream in the cone and let it melt, the cone will not hold all of the ice cream.

Therefore, no the cone will not hold all of the ice cream.

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